Ridge Runner said:
Hard Luck said:
thedigger said:
Hi Daryl
The higher the voltage,the lower the current.
I have fitted 2 sets 3.7v of lithium ion in parallel,that puts out about 15v fully charged.
Regards Frank
I have finally found someone that can do this mod for me. What Mah should the batteries be?
Can anyone help out?
Well I would aim for 3400s or even 4100s if you can find them.
john
People, please stop spreading this nonsense, some one may finish with their SPP going up in the smoke.
When you increase voltage the current will also increase, not opposite.
Ohm law, I=U/R, current equals voltage divided by resistance. You are increasing voltage by using higher voltage batteries and your resistance ( the detectors electronics ) remains same. Therefore the current drawn from the batteries will increase.
As you increase voltage by using different batteries eventually you will reach a point when something will give up and your detector will go up in puff of smoke. Most likely you will exceed voltage rating of electrolytic caps or exceed current rating of the transistor that drives he coil.
Rough calculation of current drawn from the 16V battery. With standard battery pack of 9.6V current drawn by detector is about 0.46A.
R=U/I 9.6/0.46=20.86. So, resistance or more correctly impedance of SPP as seen by battery is about 21 Ohms. Therefore 16/21=0.76.
So with 16V battery pack your SPP will using about 0.75 A.
Karl